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Zero Array Transformation IV

Difficulty: Medium


Problem Description

You are given an integer array nums of length n and a 2D array queries, where queries[i] = [l_i, r_i, val_i]. Each queries[i] represents the following action on nums:

  • Select a subset of indices in the range [l_i, r_i] from nums.
  • Decrement the value at each selected index by exactly val_i.

A Zero Array is an array with all its elements equal to 0. Return the minimum possible non-negative value of k, such that after processing the first k queries in sequence, nums becomes a Zero Array. If no such k exists, return -1.


Key Insights

  • You need to determine the minimum number of queries needed to turn all elements of nums to zero.
  • Each query allows you to decrement values over a specific range, so careful selection of which queries to apply is crucial.
  • The problem can be explored using a greedy or binary search approach to find the minimum k.

Space and Time Complexity

Time Complexity: O(n * q), where n is the length of nums and q is the length of queries. This is because, in the worst case, we might need to apply each query to all elements of nums.

Space Complexity: O(n), for storing the modified state of the nums array during processing.


Solution

To solve the problem, we can use a simulation approach. We will iterate through the queries, applying them to the nums array while maintaining a count of how many queries have been applied. For each query, we will check if applying it can potentially lead to a Zero Array. If at any point all elements become zero, we record that number of queries. If we exhaust all queries without achieving a Zero Array, we return -1.


Code Solutions

def min_queries_to_zero(nums, queries):
    n = len(nums)
    
    for k in range(1, len(queries) + 1):
        temp_nums = nums[:]
        for i in range(k):
            l, r, val = queries[i]
            for j in range(l, r + 1):
                temp_nums[j] -= val
        
        if all(x == 0 for x in temp_nums):
            return k
    
    return -1
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