Problem Description
Given two integers num
and k
, consider a set of positive integers with the following properties:
- The units digit of each integer is
k
. - The sum of the integers is
num
.
Return the minimum possible size of such a set, or -1
if no such set exists.
Key Insights
- The units digit of the integers must match
k
. - If
num
is less thank
, it is impossible to form a valid set. - A valid integer can be represented as
10 * x + k
wherex
is a non-negative integer. - The minimum size of the set can be determined based on how many times we can use integers ending with
k
to reach the sumnum
.
Space and Time Complexity
Time Complexity: O(1)
Space Complexity: O(1)
Solution
To solve this problem, we can use a greedy approach. The strategy is as follows:
- Check if
num
is less thank
. If so, return -1 since it's impossible to form a valid set. - Calculate the remainder of
num
when divided by 10. This will help us determine ifnum
can be represented using integers ending withk
. - If the remainder matches
k
, we can use integers of the formk
,(10 + k)
,(20 + k)
, etc. - The number of such integers needed is
(num - k) / 10 + 1
ifnum
is greater than or equal tok
. - If
num
is smaller thank
and not equal to 0, return -1. Ifnum
is 0, return 0 since the sum of an empty set is valid.