We use cookies (including Google cookies) to personalize ads and analyze traffic. By continuing to use our site, you accept our Privacy Policy.

SimplyLeet
TagsDisclaimersPrivacyTermsContactAbout Us

Subarray With Elements Greater Than Varying Threshold

Difficulty: Hard

Problem Description

You are given an integer array nums and an integer threshold. Find any subarray of nums of length k such that every element in the subarray is greater than threshold / k. Return the size of any such subarray. If there is no such subarray, return -1. A subarray is a contiguous non-empty sequence of elements within an array.

Key Insights

  • The problem requires finding a contiguous subarray of a given length that meets a specific condition based on the threshold.
  • The condition involves comparing each element of the subarray to a dynamically calculated value (threshold / k).
  • We can use a sliding window approach to efficiently check subarrays of varying lengths.

Space and Time Complexity

Time Complexity: O(n) - We traverse the array once. Space Complexity: O(1) - We use a constant amount of space.

Solution

To solve the problem, we can utilize a sliding window approach. We will iterate through the array while maintaining a window of size k. For each window, we check if all elements are greater than threshold / k. If we find such a window, we return its size. If we traverse the entire array without finding a valid subarray, we return -1.

Code Solutions

def subarraySize(nums, threshold):
    n = len(nums)
    for k in range(1, n + 1):  # Try all possible lengths k
        limit = threshold / k  # Calculate threshold / k
        for i in range(n - k + 1):  # Check each subarray of length k
            if all(num > limit for num in nums[i:i + k]):
                return k  # Return the size of valid subarray
    return -1  # Return -1 if no valid subarray found
← Back to All Questions