Problem Description
You are given lists of regions where the first region in each list is a parent of all subsequent regions. A region is considered to contain itself. Given two regions, region1 and region2, the task is to determine the smallest (i.e., lowest in the hierarchy) region that contains both region1 and region2.
Key Insights
- Treat each list as defining parent-child relationships, where the first element is the parent and the rest are children.
- A mapping from child to parent can be constructed for efficient look-up.
- Starting from each region, traverse upward using the parent mapping to get their full ancestry.
- The smallest common region is the first common region encountered in both ancestry paths.
- This is similar to finding the lowest common ancestor (LCA) in a tree.
Space and Time Complexity
Time Complexity: O(n + h), where n is the total number of regions and h is the height of the tree (worst-case traversal for ancestry). Space Complexity: O(n) for storing the parent mapping and O(h) for storing the ancestors of a given region.
Solution
The solution involves first building a mapping from each child region to its parent. Then, starting from region1, traverse up the parent chain and record all ancestors in a set. After that, traverse from region2 upward and check each ancestor against the set from region1. The first match will be the smallest common region containing both. This approach efficiently leverages a hash table (or dictionary) for constant-time lookups of ancestry, ensuring we quickly identify the common ancestor.