Problem Description
You are given an integer n. A string s is called good if it contains only lowercase English characters and it is possible to rearrange the characters of s such that the new string contains "leet" as a substring. Return the total number of good strings of length n. Since the answer may be large, return it modulo 10^9 + 7.
Key Insights
- A good string must contain at least the characters 'l', 'e', 'e', 't' in the required frequencies.
- For lengths less than 4, it's impossible to contain the substring "leet".
- For lengths greater than or equal to 4, we need to calculate the number of arrangements of the remaining characters while ensuring "leet" is present.
- The remaining characters can be any lowercase letters, and their arrangements can be calculated using combinatorial methods.
Space and Time Complexity
Time Complexity: O(n)
Space Complexity: O(1)
Solution
To solve this problem, we can use combinatorial mathematics to count the arrangements of the characters. The main idea is to:
- Calculate the total number of letters in the string.
- Ensure "leet" is included, then calculate the arrangements of the remaining characters.
- Use the factorial to compute permutations, adjusting for the repeated characters 'e'.
- Handle large numbers using modulo 10^9 + 7.
We will use the formula for permutations: P(n, r) = n! / (n - r)!
The approach involves:
- Counting how many total letters can be used (n - 4 for the extra letters).
- Using combinatorial counting to find the valid arrangements.