Problem Description
Given a nested list of integers, each integer’s weight is determined by how deep it is inside the list. However, the weight is calculated as "maxDepth - (current depth) + 1" where maxDepth is the maximum depth among all integers in the list. The goal is to compute the sum of each integer multiplied by its weight.
Key Insights
- First determine the maximum depth (maxDepth) of any integer in the nested list.
- Use a traversal (DFS or BFS) to calculate the depth of every integer.
- In a second pass, calculate the sum by multiplying each integer by (maxDepth - current depth + 1).
- Two passes enable conversion of a bottom-up weighted sum that essentially reverses the normal depth weight.
Space and Time Complexity
Time Complexity: O(n) where n is the total number of nested elements (each element is processed twice). Space Complexity: O(d) where d is the maximum depth due to recursion/stack usage.
Solution
The solution uses a Depth-First Search (DFS) approach with two passes. In the first pass, we traverse the nested list and record the maximum depth encountered. In the second pass, we re-traverse the list, and for each integer encountered, we compute its weighted contribution by multiplying it by (maxDepth - current depth + 1) and summing these contributions. This two-pass method is more straightforward than calculating the weight on the fly because the weight of an integer depends on the overall maximum depth which is only known after a full traversal. The key data structure used here is recursion (or an explicit stack) to handle the nested structure of the list.