Problem Description
You are given two 0-indexed arrays nums
and cost
consisting each of n
positive integers. You can increase or decrease any element of the array nums
by 1
any number of times. The cost of doing one operation on the i-th
element is cost[i]
. Return the minimum total cost such that all the elements of the array nums
become equal.
Key Insights
- The problem can be interpreted as finding a target value such that the total cost to make all elements equal to this target is minimized.
- The cost associated with each operation is different, which means some elements have a higher impact on the total cost depending on their values and the corresponding costs.
- A binary search can be employed to efficiently find the optimal target value for which the total cost is minimized.
Space and Time Complexity
Time Complexity: O(n log(max(nums)))
Space Complexity: O(1)
Solution
The problem can be solved using a binary search algorithm on the potential target values that the elements of nums
can take. The algorithm works as follows:
- Determine the range of possible target values, which is from the minimum to the maximum value in
nums
. - For each mid value in this range, calculate the total cost needed to convert all elements of
nums
to this mid value using the costs provided in thecost
array. - Adjust the search range based on whether the total cost at the mid value is less than or greater than the cost at the previous mid value.
- Continue this process until the optimal target value is found.
The key data structures used in this solution are arrays to store the nums
and cost
, and a simple loop for cost calculation.