Problem Description
Given an integer n, return any array containing n unique integers such that they add up to 0.
Key Insights
- The sum of integers can be balanced by using both positive and negative values.
- For any integer n, we can generate unique integers ranging from -(n//2) to (n//2) if n is even, or from -(n//2) to (n//2) excluding zero if n is odd.
- For n = 1, the only unique integer that sums to zero is 0.
Space and Time Complexity
Time Complexity: O(n) - We need to generate n integers. Space Complexity: O(n) - We store n integers in the resulting array.
Solution
To solve the problem, we can use a simple mathematical approach to generate unique integers. The algorithm involves creating a list of integers from -(n//2) to (n//2) while ensuring that we avoid including zero if n is odd. This guarantees that the integers are unique and their sum equals zero.