Problem Description
You are given three strings firstWord
, secondWord
, and targetWord
, each consisting of lowercase English letters from 'a' to 'j'. Return true
if the summation of the numerical values of firstWord
and secondWord
equals the numerical value of targetWord
. The numerical value of a string is determined by concatenating the letter values of each letter in the string, where the letter value is its position in the alphabet starting from 0 (i.e., 'a' -> 0, 'b' -> 1, ... 'j' -> 9).
Key Insights
- The problem requires converting strings into numerical values based on letter positions.
- The numerical value of a string is obtained by concatenating the positions of each character, then converting the resulting string into an integer.
- We only need to compare the sum of the numerical values of
firstWord
andsecondWord
to the numerical value oftargetWord
.
Space and Time Complexity
Time Complexity: O(n), where n is the maximum length of the input strings (up to 8).
Space Complexity: O(1), as we use a constant amount of space for calculations.
Solution
The solution involves the following steps:
- Create a helper function to convert a given string into its numerical value by:
- Iterating over each character.
- Calculating its position by subtracting the ASCII value of 'a' from the ASCII value of the character.
- Concatenating these positions to form a single numeric string.
- Converting that string to an integer.
- Compute the numerical values for
firstWord
,secondWord
, andtargetWord
. - Check if the sum of the first two numerical values equals the third.